Simple design with a DC relay demonstrating load balancing:
If we didn't have a second battery and the relay, adding the second resistance would decrease the resistance by half and cause the current to double which would empty the battery in half the time. What we achieved with our design is having the same electric output time.
Note that if we added the second battery in series, i2 would be 2*V/(R/2) = 4*i. Each resistance would have a current of 2i which could damage the appliance represented by the resistance (in our case, light bulbs).
Implementing the system with real parts would look like this:
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